11-5x+4x^2=

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Solution for 11-5x+4x^2= equation:


Simplifying
11 + -5x + 4x2 = 0

Solving
11 + -5x + 4x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
2.75 + -1.25x + x2 = 0

Move the constant term to the right:

Add '-2.75' to each side of the equation.
2.75 + -1.25x + -2.75 + x2 = 0 + -2.75

Reorder the terms:
2.75 + -2.75 + -1.25x + x2 = 0 + -2.75

Combine like terms: 2.75 + -2.75 = 0.00
0.00 + -1.25x + x2 = 0 + -2.75
-1.25x + x2 = 0 + -2.75

Combine like terms: 0 + -2.75 = -2.75
-1.25x + x2 = -2.75

The x term is -1.25x.  Take half its coefficient (-0.625).
Square it (0.390625) and add it to both sides.

Add '0.390625' to each side of the equation.
-1.25x + 0.390625 + x2 = -2.75 + 0.390625

Reorder the terms:
0.390625 + -1.25x + x2 = -2.75 + 0.390625

Combine like terms: -2.75 + 0.390625 = -2.359375
0.390625 + -1.25x + x2 = -2.359375

Factor a perfect square on the left side:
(x + -0.625)(x + -0.625) = -2.359375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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